# Anagram difference

Given two List of strings **a **and **b**, we need to find the minimum number of manipulations required to make each two strings anagram from the two lists.

Input :

a = "a", "jk", "abb", "mn", "abc"

b= "bb", "kj", "bbc", "op", "def"

Output : [ -1, 0, 1, 2, 3]

Explanation: Both String contains identical characters

Input :

s1 = "a"

s2 = "bb"

Output : -1

Explanation : As the length of both the strings are not same op is -1.Input :

s1 = "jk"

s2 = "kj"

Output : 0

Explanation : Both String contains identical characters.Input :

s1 = "abb"

s2 = "bbc"

Output : 1

Explanation : Here, we need to change one character

in either of the strings to make them identical. We

can change 'a' and 'c' in s1 or 'c' and 'a' in s2.Input :

s1 = "mn"

s2 = "op"

Output : 2Input :

s1 = "abc"

s2 = "def"

Output : 3

**Time Complexity: **O(n), where **n** is the length of the string.